Kelas : I/A
-->
Hukum asosiatif:
(i) a + (b + c) = (a + b) + c
A
|
B
|
C
|
a + (b + c)
|
0
|
0
|
0
|
0
|
0
|
0
|
1
|
1
|
0
|
1
|
0
|
1
|
0
|
1
|
1
|
1
|
1
|
0
|
0
|
1
|
1
|
0
|
1
|
1
|
1
|
1
|
0
|
1
|
1
|
1
|
1
|
1
|
A
|
B
|
C
|
(a + b) + c
|
0
|
0
|
0
|
0
|
0
|
0
|
1
|
1
|
0
|
1
|
0
|
1
|
0
|
1
|
1
|
1
|
1
|
0
|
0
|
1
|
1
|
0
|
1
|
1
|
1
|
1
|
0
|
1
|
1
|
1
|
1
|
1
|
(ii) a.(b.c) = (a.b). c
A
|
B
|
C
|
a.(b.c)
|
0
|
0
|
0
|
0
|
0
|
0
|
1
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
1
|
0
|
1
|
0
|
0
|
0
|
1
|
0
|
1
|
0
|
1
|
1
|
0
|
0
|
1
|
1
|
1
|
1
|
A
|
B
|
C
|
(a.b). c
|
0
|
0
|
0
|
0
|
0
|
0
|
1
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
1
|
0
|
1
|
0
|
0
|
0
|
1
|
0
|
1
|
0
|
1
|
1
|
0
|
0
|
1
|
1
|
1
|
1
|
Hukum distributif:
A
|
B
|
C
|
a + (b.c)
|
0
|
0
|
0
|
0
|
0
|
0
|
1
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
1
|
1
|
1
|
0
|
0
|
1
|
1
|
0
|
1
|
1
|
1
|
1
|
0
|
1
|
1
|
1
|
1
|
1
|
A
|
B
|
C
|
(a + b) (a + c)
|
0
|
0
|
0
|
0
|
0
|
0
|
1
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
1
|
1
|
1
|
0
|
0
|
1
|
1
|
0
|
1
|
1
|
1
|
1
|
0
|
1
|
1
|
1
|
1
|
1
|
(ii) a.(b + c) = a.b + a.c
A
|
B
|
C
|
a.(b + c)
|
0
|
0
|
0
|
0
|
0
|
0
|
1
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
1
|
0
|
1
|
0
|
0
|
0
|
1
|
0
|
1
|
1
|
1
|
1
|
0
|
1
|
1
|
1
|
1
|
1
|
A
|
B
|
C
|
a.b + a.c
|
0
|
0
|
0
|
0
|
0
|
0
|
1
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
1
|
0
|
1
|
0
|
0
|
0
|
1
|
0
|
1
|
1
|
1
|
1
|
0
|
1
|
1
|
1
|
1
|
1
|
Sederhanakan dengan cara Aljabar
1. f(x, y, z) = x’y’z + x’yz + xy’
= x’z(y’ + y) + xy’
= x’z + xy’
2. f(x,y,z) = xy + x¢z + yz
= xy + x’z + yz (x + x’)
= xy + x’z + xyz + x’yz
= xy + xyz = x’z + x’zy
= xy (1 + z ) + x’z (1 + y)
= xy + x’z
3. f(x,y,z) = (x + y)(x¢ + z)(y + z)
= (x + y)(x¢ + z)(y + z) + (y’+z’)
= (x + y) (x’ + z) (y + y’) + (y + z’) + (z + y’) + (z + z’)
= (x + y) (x’ + z)
0 komentar:
Posting Komentar